删除链表中等于给定值 val 的所有节点。
示例:
输入: 1->2->6->3->4->5->6, val = 6
输出: 1->2->3->4->5
解:很简单
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode removeElements(ListNode head, int val) {
if (head == null) {
return null;
}
while (head != null && head.val == val) {
head = head.next;
}
if (head == null) {
return null;
}
ListNode listNode = head;
while (listNode.next != null) {
if (listNode.next.val == val) {
listNode.next = listNode.next.next;
} else {
listNode = listNode.next;
}
}
return head;
}
}