在二维平面上计算出两个由直线构成的矩形重叠后形成的总面积。
每个矩形由其左下顶点和右上顶点坐标表示，如图所示。
示例:
输入: -3, 0, 3, 4, 0, -1, 9, 2 输出: 45
说明: 假设矩形面积不会超出 int 的范围。
解：
class Solution {
public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
int areaOfSqrA = (C - A) * (D - B);
int areaOfSqrB = (G - E) * (H - F);
int left = Math.max(A, E);
int right = Math.min(G, C);
int bottom = Math.max(F, B);
int top = Math.min(D, H);
int overlap = 0;
if (right > left && top > bottom)
overlap = (right - left) * (top - bottom);
return areaOfSqrA + areaOfSqrB - overlap;
}
}
